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fix incorrect order for the python SUB operator

it used to be 'BinOp(Sub(), op1, op2)', but should have been
     'BinOp(op1, Sub(), op2)'.

The rest of the changes are hanging or extra spaces.
Artem Yurchenko 2 年之前
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6130bcbd40
共有 1 个文件被更改,包括 4 次插入4 次删除
  1. 4 4
      defs.tex

+ 4 - 4
defs.tex

@@ -45,7 +45,7 @@
 \newcommand{\LangFunRefM}{\Lang_{\mathsf{FunRef}}} %F1
 \newcommand{\LangFunRefAlloc}{\ensuremath{\Lang^{\mathsf{Alloc}}_{\mathsf{FunRef}}}} %R'4
 \newcommand{\LangLam}{$\Lang_\lambda$} %R5
-\newcommand{\LangLamFunRef}{$\Lang_\lambda^{\mathsf{FunRef}}$} 
+\newcommand{\LangLamFunRef}{$\Lang_\lambda^{\mathsf{FunRef}}$}
 \newcommand{\LangLamM}{\ensuremath{\Lang_\lambda}} %R5
 \newcommand{\LangCLam}{$\CLang_{\mathsf{Clos}}$} %C4
 \newcommand{\LangCLamM}{\CLang_{\mathsf{Clos}}} %C4
@@ -208,9 +208,9 @@
 \newcommand{\READ}{{\key{Call(Name('input\_int'),[])}}}
 \newcommand{\CREAD}{\key{input\_int()}}
 \newcommand{\NEG}[1]{{\key{UnaryOp(USub(),} #1\code{)}}}
-\newcommand{\ADD}[2]{{\key{BinOp}\LP #1\code{,} \key{Add()}\key{,}#2\code{)}}}
-\newcommand{\ADDP}[2]{{\key{BinOp}\LP #1\code{,} \key{Add()}\key{,}#2\code{)}}}
-\newcommand{\SUB}[2]{{\key{BinOp}\LP \key{Sub()}\key{,}#1\code{,}#2\code{)}}}
+\newcommand{\ADD}[2]{{\key{BinOp}\LP #1\code{,}\key{Add()}\key{,}#2\code{)}}}
+\newcommand{\ADDP}[2]{{\key{BinOp}\LP #1\code{,}\key{Add()}\key{,}#2\code{)}}}
+\newcommand{\SUB}[2]{{\key{BinOp}\LP #1\code{,}\key{Sub()}\key{,}#2\code{)}}}
 \newcommand{\PRINT}[1]{{\key{Expr}\LP\key{Call}\LP\key{Name}\LP\key{'print'}\RP\key{,}\LS#1\RS\RP\RP}}
 \newcommand{\CPRINT}[1]{\key{print}\LP #1\RP}
 \newcommand{\EXPR}[1]{{\key{Expr}\LP #1\RP}}