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fix incorrect order for the python SUB operator

it used to be 'BinOp(Sub(), op1, op2)', but should have been
     'BinOp(op1, Sub(), op2)'.

The rest of the changes are hanging or extra spaces.
Artem Yurchenko 2 年 前
コミット
6130bcbd40
1 ファイル変更4 行追加4 行削除
  1. 4 4
      defs.tex

+ 4 - 4
defs.tex

@@ -45,7 +45,7 @@
 \newcommand{\LangFunRefM}{\Lang_{\mathsf{FunRef}}} %F1
 \newcommand{\LangFunRefAlloc}{\ensuremath{\Lang^{\mathsf{Alloc}}_{\mathsf{FunRef}}}} %R'4
 \newcommand{\LangLam}{$\Lang_\lambda$} %R5
-\newcommand{\LangLamFunRef}{$\Lang_\lambda^{\mathsf{FunRef}}$} 
+\newcommand{\LangLamFunRef}{$\Lang_\lambda^{\mathsf{FunRef}}$}
 \newcommand{\LangLamM}{\ensuremath{\Lang_\lambda}} %R5
 \newcommand{\LangCLam}{$\CLang_{\mathsf{Clos}}$} %C4
 \newcommand{\LangCLamM}{\CLang_{\mathsf{Clos}}} %C4
@@ -208,9 +208,9 @@
 \newcommand{\READ}{{\key{Call(Name('input\_int'),[])}}}
 \newcommand{\CREAD}{\key{input\_int()}}
 \newcommand{\NEG}[1]{{\key{UnaryOp(USub(),} #1\code{)}}}
-\newcommand{\ADD}[2]{{\key{BinOp}\LP #1\code{,} \key{Add()}\key{,}#2\code{)}}}
-\newcommand{\ADDP}[2]{{\key{BinOp}\LP #1\code{,} \key{Add()}\key{,}#2\code{)}}}
-\newcommand{\SUB}[2]{{\key{BinOp}\LP \key{Sub()}\key{,}#1\code{,}#2\code{)}}}
+\newcommand{\ADD}[2]{{\key{BinOp}\LP #1\code{,}\key{Add()}\key{,}#2\code{)}}}
+\newcommand{\ADDP}[2]{{\key{BinOp}\LP #1\code{,}\key{Add()}\key{,}#2\code{)}}}
+\newcommand{\SUB}[2]{{\key{BinOp}\LP #1\code{,}\key{Sub()}\key{,}#2\code{)}}}
 \newcommand{\PRINT}[1]{{\key{Expr}\LP\key{Call}\LP\key{Name}\LP\key{'print'}\RP\key{,}\LS#1\RS\RP\RP}}
 \newcommand{\CPRINT}[1]{\key{print}\LP #1\RP}
 \newcommand{\EXPR}[1]{{\key{Expr}\LP #1\RP}}