Jeremy Siek 3 年之前
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7ff9bc3841
共有 1 個文件被更改,包括 4 次插入4 次删除
  1. 4 4
      book.tex

+ 4 - 4
book.tex

@@ -5874,10 +5874,10 @@ challenge.
 
 
 {\if\edition\racketEd      
 {\if\edition\racketEd      
 To motivate the need for move biasing we return to the running example
 To motivate the need for move biasing we return to the running example
-but this time use all of the general purpose registers.  So we have
+but this time we use all of the general purpose registers.  So we have
 the following mapping of color numbers to registers.
 the following mapping of color numbers to registers.
 \[
 \[
-  \{ 0 \mapsto \key{\%rcx}, \; 1 \mapsto \key{\%rdx}, \; 2 \mapsto \key{\%rsi} \}
+  \{ 0 \mapsto \key{\%rcx}, \; 1 \mapsto \key{\%rdx}, \; 2 \mapsto \key{\%rsi}, \ldots \}
 \]
 \]
 Using the same assignment of variables to color numbers that was
 Using the same assignment of variables to color numbers that was
 produced by the register allocator described in the last section, we
 produced by the register allocator described in the last section, we
@@ -6025,8 +6025,8 @@ were \code{w} and \code{y}.
 %
 %
 Last time we chose to color \code{w} with $0$. But this time we see
 Last time we chose to color \code{w} with $0$. But this time we see
 that \code{w} is not move related to any vertex, but \code{y} is move
 that \code{w} is not move related to any vertex, but \code{y} is move
-related to \code{t}.  So we choose to color \code{y} the same color as
-\code{t}, $0$.
+related to \code{t}.  So we choose to color \code{y} with $0$, the
+same color as \code{t}.
 \[
 \[
 \begin{tikzpicture}[baseline=(current  bounding  box.center)]
 \begin{tikzpicture}[baseline=(current  bounding  box.center)]
 \node (rax) at (0,0) {$\ttm{rax}:-1,\{0,-2\}$};
 \node (rax) at (0,0) {$\ttm{rax}:-1,\{0,-2\}$};