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@@ -1,56 +0,0 @@
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-This is very exciting, we're going to create our own boot sector!
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-
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-Theory
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-------
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-
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-When the computer boots, the BIOS doesn't know how to load the OS, so it
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-delegates that task to the boot sector. Thus, the boot sector must be
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-placed in a known, standard location. That location is the first sector
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-of the disk (cylinder 0, head 0, sector 0) and it takes 512 bytes.
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-
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-To make sure that the "disk is bootable", the BIOS checks that bytes
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-511 and 512 of the alleged boot sector are bytes `0xAA55`.
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-
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-This is the simplest boot sector ever:
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-
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-```
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-e9 fd ff 00 00 00 00 00 00 00 00 00 00 00 00 00
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-00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
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-[ 29 more lines with sixteen zero-bytes each ]
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-00 00 00 00 00 00 00 00 00 00 00 00 00 00 55 aa
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-```
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-
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-It is basically all zeros, ending with the 16-bit value
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-`0xAA55` (beware of indianness, x86 is little-endian).
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-The first three bytes perform an infinite jump
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-
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-Simplest boot sector ever
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--------------------------
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-
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-You can either write the above 512 bytes
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-with a binary editor, or just write a very
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-simple assembler code:
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-
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-```nasm
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-; Infinite loop (e9 fd ff)
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-loop:
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- jmp loop
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-
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-; Fill with 510 zeros minus the size of the previous code
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-times 510-($-$$) db 0
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-; Magic number
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-dw 0xaa55
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-```
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-
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-To compile:
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-`nasm -f bin boot_sect_simple.asm -o boot_sect_simple.bin`
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-
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-> OSX warning: if this drops an error, read chapter 00 again
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-
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-I know you're anxious to try it out (I am!), so let's do it:
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-
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-`qemu boot_sect_simple.bin`
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-
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-You will see a window open which says "Booting from Hard Disk..." and
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-nothing else. When was the last time you were so excited to see an infinite
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-loop? ;-)
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Carlos Fenollosa